bantu dong gaisss pake cara yahh jangan asal²an
A. 2√29
Penjelasan dengan langkah-langkah:
AG² = p² + l² + t²
= 8² + 6² + 4²
= 64 + 36 + 16
= 116
AG = √116
= √(4 x 29)
= 2√29
[tex]ag = \sqrt{ {ab }^{2} + {bc}^{2} + {cg}^{2} } \\ \\ = \sqrt{ {8}^{2} + {6}^{2} + {4}^{2} } \\ \\ = \sqrt{64 + 36 + 16} \\ \\ = \sqrt{116} \\ \\ = 2 \sqrt{29} [/tex]
jawabannya opsi a.2√29
maaf kalo salah
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